Pleas help me with this question?

when we cross Ss with Ss and we get SS, Ss,Ss, and ss.


so what are the chances that first child will show keratosis( it is due to dominant gene so its is Ss OR SS)


answer is 75% but how


what are th chances that 2nd child will show keratosis ANSWER IS 75% AGAIN HOW?


3RD ONE


75% HOW


AND WHAT IS 4TH CHILD %

Pleas help me with this question?
If keratosis is carried by the dominant allele (S) and will be expressed phenotypically if the dominant allele (S) is present, so by crossing two heterozygotes (Ss x Ss) you will get the following:


Ss x 2 = keratosis


SS x 1 = keratosis


ss x 1 = no keratosis


So from this you would have a 75% chance that a progeny of this parent generation (Ss x Ss) will exhibit keratosis.


You only have a 25% chance that the progeny of this cross will not exhibit keratosis (ss).


Hope this helps a little bit!
Reply:S is a dominant so it is expressed both hetro and homo so the child will have 75% of having S but 50% to be a carrier s and 25% of homo s

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